0=x^2+3x+2,25-1

Solution for 0=x^2+3x+2,25-1 equation:

0=x^2+3x+2.25-1

We move all terms to the left:

0-(x^2+3x+2.25-1)=0

We add all the numbers together, and all the variables

-(x^2+3x+2.25-1)=0

We get rid of parentheses

-x^2-3x-2.25+1=0

We add all the numbers together, and all the variables

-1x^2-3x-1.25=0

a = -1; b = -3; c = -1.25;
Δ = b2-4ac
Δ = -32-4·(-1)·(-1.25)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-2}{2*-1}=\frac{1}{-2}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+2}{2*-1}=\frac{5}{-2}
=-2+1/2
$